FRANSAT VIA EMU 5°W TEST !! [CHAT HERE, NO KEYS]

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unperfect820

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Good morning
And how we do
It's useless without explanations
it's very difficult to implement
Thank you
 
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dydyer

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127
It's like with TNT, you manage to find everything on your own, big bullshit, stop posting anything ...
 

fiji

Member
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1,074
I work in vplug & add M0 seed key provider/dcw ok but no video
M0 seed key use for only Irteo cas.
19.2E = 6TER 11817V29700 (it is single provider read)

for full screen click on image
 

EnoSat

Senior Member
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1,952
in vplug (viaccess.mdl) missing new algo for D2,
M0 is not important at the moment
 

fiji

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1,074
RAYLAN RR-YS9 V1.09.21927 updated 24062020 tnt + francesat work via emu .
 

EnoSat

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this video doesnt work.
file OK
capture-005-04072020-125515.png
 

chenxinting12

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2
Hi,

I want to show some information that I got.
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
nano:9003D00070
nano: D2020E00
nano:4106BA866500CD76
nano:BA0250C1
nano:BC030A322D
nano:431020B51288C8891078A400C2E06B141042
nano:44A41FF6E57BCDD48A89E952E06C1479C7C2EC28FE505141D8F5F59175FAA0A773AF47248F58156A27FDE8F20C6B2EB203A6C086E6DDA2E2D6FE9FCE3CD9AF522AB8C5DF6034786E2B80DD4B9264887CEFB0E6E11FAB90BE6E555F74E35851557BC88CBBD8571C51D9B36EFE2D1128F2A48D84B6CD4ADF07530D46A41BC8CDE59547A40521F140D8198D30718CE1BC1DF4BF3808E5F01F3C3CC679D24C491A974958D831E3B2
nano:6593010402D18F170301021010C8D7A3A6AF8E31C82304BC3F3E1790D411105464A50FA9C5E7D3E14644725238A316030103101081EFEF136F7C60409A2016A98D032BFA11108CCF339E78119AAA4EF47CE323B417B903010410108F0F4A4D1257D52091832F9EA9C403761110D2C7D28E651937622371DA8077D541EF3016D2020D000110A218C5EE345776DD0D39501D84CB9A65
subnano:010402D18F17
subnano:030102
subnano:1010C8D7A3A6AF8E31C82304BC3F3E1790D4
subnano:11105464A50FA9C5E7D3E14644725238A316
subnano:030103
subnano:101081EFEF136F7C60409A2016A98D032BFA
subnano:11108CCF339E78119AAA4EF47CE323B417B9
subnano:030104
subnano:10108F0F4A4D1257D52091832F9EA9C40376
subnano:1110D2C7D28E651937622371DA8077D541EF
subnano:3016D2020D000110A218C5EE345776DD0D39501D84CB9A65
ssubnano: D2020D00
ssubnano:0110A218C5EE345776DD0D39501D84CB9A65
nano:660100
nano:670402D18F17
nano:F00478EC9B00

There is a new nano 65 instead of the old nano 68.
And in this nano65, there are three nano 10 and 11.
I guess they are 3-level input of some keyladder, maybe aes cbc. I don't know.
And in nano 30, there are nano D2 and nano 01. This is old format.

So the problem is how to decrypt the nano 01 in nano 30 by the nano 10 and nano 11 in new nano 65.:mad:
 

Shamra

Registered
Messages
196
Hi,

I want to show some information that I got.
<…>
nano:F00478EC9B00

There is a new nano 65 instead of the old nano 68.
And in this nano65, there are three nano 10 and 11.
I guess they are 3-level input of some keyladder, maybe aes cbc. I don't know.
And in nano 30, there are nano D2 and nano 01. This is old format.

So the problem is how to decrypt the nano 01 in nano 30 by the nano 10 and nano 11 in new nano 65.:mad:


I said earlier, but I will repeat:
We need an algorithm for Nano213 and the actual(!) key(s).
 
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